Riddles!

[Peltito]

It seems as though this forum's slowed down lately and since I've just returned I'd like to add something. How about a thread of riddles? Person who solves it gets to leave a new one. We'll start with an easy one, took me about 2 minutes to do when I was waiting for class to start.

What is greater than God?
More evil than the Devil?
The rich need it,
The poor have it,
and if you eat it, you die?

Good luck!

[adamantium]

nothing

[Peltito]

Originally posted by Peltito
Person who solves it gets to leave a new one.

[adamantium]

Okay, I blow at riddles, so this will probably be freaking easy.

28 White Horses Upon A Red Hill
First They Champ
Then They Stamp
Then They Stand Still.

[Palmy]

teeth

[MindFlare]

Originally posted by adamantium
Okay, I blow at riddles, so this will probably be freaking easy.

28 White Horses Upon A Red Hill
First They Champ
Then They Stamp
Then They Stand Still.

You have great reading comprehension.

Person who solves it gets to leave a new one


Pelito...WILD guess. (And I mean wild). Pride ?

[Acharne]

Mind, while that is a very good answer, the actual answer to the riddle was nothing, and adamantium beat you to it.

edit: I think that it's Palmy's turn to put a riddle up to be solved.

[Peltito]

Darnit, I missed a riddle!!! Ok, Palmy, place a new riddle please!

[Palmy]

Why do firemen wear suspenders?

[Tripwire]

Lich?

[dexy]

k i dont know if its my turn to post a riddle but here is one anyway
i got it from a book i think or off the net a long time ago
so i hope i dont get sued for copyright or somthing and of course its not exactly right but ill try my best

There was a boxing match on tuesday night... it lasted 2 minutes and ended in a KO (knock out)... but no man was able to get a punch off... how did the knock out occur to the boxer?


wooo woooo i hope i didnt screw it up...

[permafried]

Ether? Or some such other sleeping agent on the gloves?

[agent_ze]

women's boxing :)



LAura's father has 5 daughters

1- Papa
2- Pepe
3- Pipi
4- ?
5- Pupu





What's the name of nr 4?

[axe]

laura obviously

[Sterkarm]

popo

[permafried]

What is a five letter word which becomes shorter with two letters added onto it?

[Tone-Loc]

Originally posted by permafried
What is a five letter word which becomes shorter with two letters added onto it?

short + er = shorter

[permafried]

bah Tone-loc


Before Sir Richard Burton attemped to discover the source of the Nile, which was the world's longest river?

[Tone-Loc]

Originally posted by permafried
bah Tone-loc


Before Sir Richard Burton attemped to discover the source of the Nile, which was the world's longest river?

Whether it was not known at the time or not, the world's longest river would still have been the Nile.

[Cyberdemon]

1
11
21
1211
111221
312211
13112221

What should the next number be in this sequence?

[SithDrummer]

Originally posted by Cyberdemon
1
11
21
1211
111221
312211
13112221

What should the next number be in this sequence?

didn't wanna guess until i was sure, but i'm tired and going to bed, so here's my answer:

11133131

[ZdrozZ]

If you have contact with an alien race via telecommunication (only tv, radio etc, you cant meet them in space...), how do you explain them where 'left' and 'right' is?

I really wonder if someone can answer this :p
Hint: it has something to do with the parity of the universe, or the lack off...

[Palmy]

A box without hinges
Key or lid
Yet golden treasure inside is hid
It's a hot pocket.

[[RiCE]cancer]

didn't wanna guess until i was sure, but i'm tired and going to bed, so here's my answer:

11133131

I'll have to disagree and say 1113213211.

[SithDrummer]

Originally posted by [TiTz]-Auron
this is a pretty easy one, and Im sure anyone who reads a lot has seen it. Anyway, heres an easy one

A box without hinges
Key or lid
Yet golden treasure inside is hid

hint: if you've read The Hobbit you'll get it.

it's an egg!

[Cyberdemon]

Originally posted by [RiCE]cancer
I'll have to disagree and say 1113213211.

Bingo. Sith, here's a hint: read each digit individually.

[[RiCE]cancer]

WARNING: ANSWER TO SEQUENCE RIDDLE









Each set of numbers is a "coded" representation of the last. It's sort of hard to explain.

We start with "1". The code is to put a number for how many of the same digits there are in a row, followed by what digit it is. In the number "1" we have one digit in a row, and the digit is "1". We denote this as "11", meaning a string of 1 1. In "11" we have two ones in a row: 21. In 21, there is one two, followed by one one: 1211. In "1211" we have one one, folowed by one two, followed by two ones: 111221. Etcetera. Apply it to 13112221 and you get 1113213211.





END SPOILER

[Cyberdemon]

There is one word in the English language, nine letters long, from which you can repeatedly remove a single letter (right down to the last one) and have it remain a proper, common word each time.

What are the starting and resulting words?

[Famine-]

What has walls and lips.

[Tone-Loc]

Originally posted by Famine-
What has walls and lips.

Your mother? or any other female for that matter... (vagina)

Originally posted by Cyberdemon
There is one word in the English language, nine letters long, from which you can repeatedly remove a single letter (right down to the last one) and have it remain a proper, common word each time.

What are the starting and resulting words?

heroines
heroine
heroin
heron
hero
her
he
uh... e!

closest I could think of.

[[RiCE]cancer]

I fooled around with it for a while yesterday. It has to start with an A or an I because those are the only two single letters that make a word.

[[RiCE]cancer]

I'm not sure I know what you mean.

I'd assume it would end in an s or other plural notation, so you can remove it and get the singular form. Yesterday, I tried to search all of the words that started with A that I could. It's not that hard...make a list of all the two letter A words: ad, am, an, as, at. Then try to add a letter to the end of each of those. I carried it all the way out and didn't find anything past six letters. Either I missed something or it starts with an I.

Edit: I think the largest word that fit the criteria I was able to get from that method (A's only) was "antics" and I'm not even sure if "anti" counts. I'll do the I words today if I get extremely bored.

Edit #2: Ok, now I understand what you're asking. Good question. Cyberdemon, can the letter that's being removed come from anywhere or does it have to be taken off of the end of the word?

[Cyberdemon]

Originally posted by [RiCE]cancer

Edit #2: Ok, now I understand what you're asking. Good question. Cyberdemon, can the letter that's being removed come from anywhere or does it have to be taken off of the end of the word?

From anywhere - sorry I wasn't more specific on that one, this one's always kind of tricky to word right.

Reptawr's "heroines" guess was excellent, but that's only eight letters :).

[CountBubba]

the answer is really startling!

startling
starling
staring
string
sting
sing
sin
in
i

[permafried]

Well, I think Count got that one so I'll post another easy one:

There is a town where 5 percent of all the people living there have unlisted phone numbers. If you selected 100 names at random from the town's phone directory, on average, how many of these people would have unlisted phone numbers?

[Palmy]

None of them.

[permafried]

bah, mine are too easy, but i'll post one last one:


There is one five letter word in the English language that is always pronounced wrong. What is this word?

[BluRRPy]

wrong

[Rapt]

1.) I come into this world without flesh or skin, I have no mother or father, I speak once and am never heard from again. What am I?

2.) I am everywhere, but say my name and I vanish. I am...

[agent_ze]

Durin the ww2, the British royal air force would use Bombers to attack the enemy and other planes to escort the bombers. Unfortunatly that wasn't enough, as the enemy anti air batteries would still be able to target and hit the bombers. When the damaged bombers flew back to their base a RAF engineer analised them, trying to find a way to protect them. Adding a steel shield to the whole bottom of the bombers would make them to heavy to fly, so a solution had to be found to make a shield able to protect the bombers bot too heavy. What did the engineer do?

[agent_ze]

Originally posted by Rapture


2.) I am everywhere, but say my name and I vanish. I am...


silence

[k9black`]

theres this guy walking down the street, he notices soemthing shiny in the dirt. he picks it up, its a coin. its date says 200B.C.

he guy thought WOW this must be worth alot! he took it to a coin dude, whatever their name is. and he took it back into his office and studied it for a while. he came back out and told the man that had brought it in that it was fake. how did he know it was fake?




^ this ones pretty easy, ill have harder ones later

[agent_ze]

nobody can asnwer mine? :\

[k9black`]

yay for red


agent thats nto really a riddle, its history

[CountBubba]

Originally posted by Rapture
1.) I come into this world without flesh or skin, I have no mother or father, I speak once and am never heard from again. What am I?

the only thing i can think of is an echo...although those can be heard more than once...

[Arcadion]

Hoardes of gold within my walls
yet no man made them.
Hundreds of spears sentry my walls
yet no man guards them.

[Donut]

Translated from Russian:

2 Rings
2 Ends
1 nail in the middle

what is it?

[drone]

what color is a blue house?
what color is a red house?
what color is a yellow house?
what color is a brown house?
what color is a gray house?
what color is a white house?
what color is a green house?

[Donut]

greenhouse = made of glass


edit: somebody get mine!!!


edit2:

What do you call a nut on a wall? A walnut
What do you call a nut on a chest? Chestnut
What do you call a nut on the chin?

[Donut]

wrong :( (unless im missing some southpark joke)

[Palmy]

A moneyshot?

[CountBubba]

Originally posted by Arcadion
Hoardes of gold within my walls
yet no man made them.
Hundreds of spears sentry my walls
yet no man guards them.

bees nest

[permafried]

This sig image is inappropriate. Exposed breasts are not allowed because we're whiny bitches and boobs scare us


lmao

[Donut]

Originally posted by |3eeR| duck
a dick in your mouth =D

winnar!

but somebody still needs to get this one:

2 Rings
2 Ends
1 Nail in the middle

What is it?

[Cyberdemon]

Originally posted by drone
what color is a blue house?
what color is a red house?
what color is a yellow house?
what color is a brown house?
what color is a gray house?
what color is a white house?
what color is a green house?

I don't see how the "a greenhouse is made of glass" answer works...a greenhouse is made of glass, sure, but a green house is just that - a house that's green. :D

Ahh well, another "name that word" riddle:

What English word becomes its own past tense when its letters are rearranged?

[Donut]

Originally posted by Sleepy Mexican
Only thing i can think of is marriage :eek:

Nope ;)

Hint: it's an object.

[CountBubba]

What English word becomes its own past tense when its letters are rearranged?

eat...ate

[CountBubba]

Originally posted by Donut
2 Rings
2 Ends
1 Nail in the middle


a bell?

[Ves]

Originally posted by Arcadion
Hoardes of gold within my walls
yet no man made them.
Hundreds of spears sentry my walls
yet no man guards them.

pineapple? heh..

[Ves]

Originally posted by Donut
Translated from Russian:

2 Rings
2 Ends
1 nail in the middle

what is it?

a finger? two rings = the bendy parts, two ends are the two ends of the finger... and the nail is the nail, but it really isn't in the middle..
i'm bad at this game

[Donut]

Both good guesses, but no :D

[osiris]

These are pretty easy:

What state is surrounded by the most water?

George, Helen, and Steve are drinking coffee.
Bert, Karen, and Dave are drinking soda.
Using logic, is Elizabeth drinking coffee or soda?

I cannot be felt, seen or touched;
Yet I can be found in everybody;
My existence is always in debate;
Yet I have my own style of music.
What Am I?

[permafried]

Originally posted by osiris
I cannot be felt, seen or touched;
Yet I can be found in everybody;
My existence is always in debate;
Yet I have my own style of music.
What Am I?


mmmmmmm...... soul?

[Rapt]

1.) I come into this world without flesh or skin, I have no mother or father, I speak once and am never heard from again. What am I?

A fart.

I stole it from the Bob and Tom show.

[Donut]

Originally posted by Donut
Translated from Russian:

2 Rings
2 Ends
1 nail in the middle

what is it?


Scissors

[osiris]

Originally posted by permafried
mmmmmmm...... soul?
yessir

[Cyberdemon]

Originally posted by osiris
These are pretty easy:

What state is surrounded by the most water?

Hawaii!

Originally posted by osiris

George, Helen, and Steve are drinking coffee.
Bert, Karen, and Dave are drinking soda.
Using logic, is Elizabeth drinking coffee or soda?

Coffee. Elizabeth has two E's in her name.

[Donut]

must keep thread alive with a terrible riddle =/

It shoots at your ankle, and ends up at your nose.

[Tone-Loc]

Originally posted by Donut
must keep thread alive with a terrible riddle =/

It shoots at your ankle, and ends up at your nose.

a fart?

[Donut]

yup

[Milosenpotion]

You take me into a room, light my head on fire, I cry, and then you cut my head off. What am I?

[Tone-Loc]

My first 3 wives? Fuck you cops, you will never be able to prove it was me!!

Well seeing as how no one should know about that, I will say its a candle.

[Donut]

not just any candle...a birthday candle!

[Milosenpotion]

Candle is right. Post more riddles!

[Streetwolf]

Whoever gets this gets a cookie - maybe.

Riddle #1: There are 12 coins on a table. I tell you that 11 of these coins are real, and ONE is counterfeit. The coins were designed so well that they all look identical; in fact, the ONLY difference between the real ones and the counterfeit is its weight.

I give you a balance scale (two sides, you put a weight on each side. Whichever side drops down is heavier; if the two sides weigh the same the two sides will stay in the middle). Using the scale only THREE times, can you figure out which coin is the counterfeit? KEEP IN MIND --> you do NOT know if the coin weighs more or less than the others.

Riddle #2: I put a blindfold on you and sit you down in front of a table. I have a piggy bank full of pennies, which I dump onto the table. There are a very large number of pennies. I tell you that 128 of the pennies are heads up and the rest are tails up. How can you create two subgroups of pennies, each with the same number of heads facing up?

Riddle #3 (the FUN one): Five friends, Andrew, Bernard, Claude, Donald, and Eugene, each have a son and a daughter. Their families are so close that each has married his daughter to the son of one of his friends, and as a result the daughter-in-law of the father of Andrew's son-in-law is the sister-in-law of Bernard's son, and the son-in-law of the father of Claude's daughter-in-law is the brother-in-law of Donald's daughter.

But although the daughter-in-law of the father of Bernard's daughter-in-law has the same mother-in-law as the son-in-law of the father of Donald's son-in-law, the situation is simplified by the fact that no daughter-in-law is the sister-in-law of the daughter of her father-in-law.

Who married Eugene's daughter?

Riddle #4 (the easy one): Which weighs more, a pound of feathers or a pound of gold?

[Sleepy Mexican]

Originally posted by Streetwolf
Whoever gets this gets a cookie - maybe.

Riddle #1: There are 12 coins on a table. I tell you that 11 of these coins are real, and ONE is counterfeit. The coins were designed so well that they all look identical; in fact, the ONLY difference between the real ones and the counterfeit is its weight.

I give you a balance scale (two sides, you put a weight on each side. Whichever side drops down is heavier; if the two sides weigh the same the two sides will stay in the middle). Using the scale only THREE times, can you figure out which coin is the counterfeit? KEEP IN MIND --> you do NOT know if the coin weighs more or less than the others.


5 coins on each side. If they're even, the bastard coin is the fake. If not, then take the 5 that are slightly heavier, toss the 5 and the bastard coin to the side, now just 5 left, 2 scale uses. Put 2 on each side. If even, the new bastard coin is the fake. Now take the 2 that are slightly heavier, and toss the other 2 with the real ones. Measure those 2, heavier coin is the fake.

[Streetwolf]

Errr no.

Remember, the counterfeit coin weighs DIFFERENTLY than the others. It could be heavier... or it could be lighter. You don't know. You have to find another way to figure it out. After you figure out which is the counterfeit coin, you figure out if it's heavier or lighter.

[t00t]

Originally posted by Streetwolf

Riddle #4 (the easy one): Which weighs more, a pound of feathers or a pound of gold?

They weigh the same :P

I don't even wanna think about those other ones, lol. Good questions though.

[Streetwolf]

Originally posted by t00t
They weigh the same :P

Ooooh nice try! But... WRONG!! :D

Two more possibilities... someone include a reason too, thx.

[Donut]

Originally posted by Streetwolf
Ooooh nice try! But... WRONG!! :D

Two more possibilities... someone include a reason too, thx.

t00t's answer is wrong? :confused:

[t00t]

Uh I don't see how it's wrong. The volume occupied by the feathers would be much greater then the gold because of the density, but seeing as each substance is 1 pound, they will each weigh the same... ?! What am I missing here?

Weight is Force due to Gravity, Fg. Force due to gravity is defined as mass, m, times acceleration due to gravity, g=9.81m/s^2.

So the equation to calculate weight is Fg=mg. g is a constant, and it was stated that m in both cases is 1 pound (.45kg). Since the variable in both cases is the same, Fgfeather and Fggold are the same: 4.41 N.

Am I still wrong? :confused:

[t00t]

I don't know why, but I decided to try riddle #3

Originally posted by Streetwolf

Riddle #3 (the FUN one): Five friends, Andrew, Bernard, Claude, Donald, and Eugene, each have a son and a daughter. Their families are so close that each has married his daughter to the son of one of his friends, and as a result the daughter-in-law of the father of Andrew's son-in-law is the sister-in-law of Bernard's son, and the son-in-law of the father of Claude's daughter-in-law is the brother-in-law of Donald's daughter.

But although the daughter-in-law of the father of Bernard's daughter-in-law has the same mother-in-law as the son-in-law of the father of Donald's son-in-law, the situation is simplified by the fact that no daughter-in-law is the sister-in-law of the daughter of her father-in-law.

Who married Eugene's daughter?



My answer is Eugene's daughter is married to Bernard's son.

Now the way I came to this:
Andrew
Andrew's Son+(Bernard's Daughter)
Andrew's Daughter+(Donald's Son)?? father of ??'s daughter-in-law's is the siter in law of BS

B
BS+ED
BD+(AS)

C
CS+(DD)?? father of ??'s son in law is the brother in law of DS
CD+(ES)

D
DS+(AD)
DD+(CS)??

E
ED+BS
ES+(CD)?? has the same mother as father of ?? of DD+??

Hopefully you understand that.

Oh, and Streetwolf, if that isn't right, I demand you show me how to find the correct answer!

Guess I'll try one of those coin quetions, because there's no way I'm touching this beast again :P

[Streetwolf]

I don't have the answer in front of me, but off the top of my head you are correct with #3; however, you are STILL incorrect with #4.

[KaY-PeE]

how is he incorrect??! they wiegh the same, POUND of feathers and POUND of gold same mass.

[Streetwolf]

Not the correct answer, man. But I'm sure you'll hit yourself when you hear the correct answer and the reason.

[axe]

A pound of feathers is heavier since feathers are weighed by avoirdupois weight while gold is weighed in troy (or apothecary) weight and 1 lb avoirdupois = 1.21528 lbs troy. The precious metals, such as gold, silver, platinum and palladium, are usually quoted in troy ounces while most of our measurements (in the U.S.) are in the avoirdupois system.

(I cheated)

[t00t]

Originally posted by Streetwolf
you are STILL incorrect with #4.

Only on account of villainy!

The answer you are looking for, I'm guessing, is that the feathers 'weigh' more. The proof you would be looking for to support this is that feathers are measured in avoirdupois pounds(lb av), and gold is measured in troy pounds(lb t). The conversion is 1 lb av = 1.215 lb t, and therefor, the pound avoirdupois would 'weigh' more.

The question is only tricky at all because you leave out certain information, such as there is no indication that the items given for comparison are being massed in anything other then regular universal pounds. And furthermore, the comparison asked for at the end is comparing their masses, not their weight.

So in conclution, boo, lame question :P

EDIT: Dammit! Just a little too late to get that in first, shouldn't have been so wordy I guess :P

[Streetwolf]

When you assume, you make an ass of u and me.

If you measure gold, you should be measuring it in troy pounds. When you measure the weight of feathers, you use "regular" pounds (the ones we use normally).

I never said anything else :).

And it doesn't compare masses...

[t00t]

Originally posted by Streetwolf

And it doesn't compare masses...
Yes it does.

Mass is a property of matter equal to the measure of an object's resistance to changes in either the speed or direction of its motion. The mass of an object is not dependent on gravity and therefore is different from but proportional to its weight.

Weight is the force with which a body is attracted to Earth or another celestial body, equal to the product of the object's mass and the acceleration of gravity.

Not that it really makes a difference since most people get those two confused, and know what you meant anyways. But it led me on the wrong track for a while :P

[Streetwolf]

And weight is measured in pounds. You are comparing two different weights. A troy pound, however, weighs less than an avoirdupois pound.

Mass is measured in grams. I see no grams here.

[t00t]

Mass is measured in kilograms, weight is measured in newtons. Unless americans measure it in pounds?!

[Streetwolf]

Ya. Pounds implies weight (over here). I take it you are not from here then :p.

Okay just solve #'s 1 and 2!! :)

[Rimuladas]

I am black of eye and bright of hair. I fast in to the ground and follow my lord as he races around the world. What am I?

[MyN]

Shadow

[Moniker]

Originally posted by Streetwolf
And weight is measured in pounds. You are comparing two different weights. A troy pound, however, weighs less than an avoirdupois pound.

Mass is measured in grams. I see no grams here. Ah, you may be feeling smart after that, but it's easily contested.

Still, a gram of gold is a gram of gold. Unless you cite that the gold was weighted under troy pounds, and feathers weighted as avoirdupois one can only assume that it is weighed from the same standard the feathers are. 2 things, weighed in comparison, are usually weighed on the same scale for evaluation. I could put 3 grams of sugar on a kitchen scale, and 3 grams of sugar on a truck scale, and there would be inherent margin of error because it's not the same scale. Hence, your answer is illogical.

For example, if I say log x = 2log y, I assume both are base ten, not one is base ten and the other base two, such as log x = 2 log(2) y [it's been a long time, someone correct me if im wrong on that] -- this must be specified ahead of time. It is customary to assume they are both base ten.

Therefore, the fault lies on you for not providing enough information.

One could argue that ignorance of the law is not a valid defense of the law, but unless that law is made known, ignorance of it is perfectly accetable. If you're curious FOIA (Freedom of Information Act) is sort of based on this principle.

It's your own fault that you didn't state they were both weighted according to their respective standards.

SO THERE. (I'm bored, if you can't tell)

[LuTze]

Originally posted by Streetwolf
Whoever gets this gets a cookie - maybe.

Riddle #1: There are 12 coins on a table. I tell you that 11 of these coins are real, and ONE is counterfeit. The coins were designed so well that they all look identical; in fact, the ONLY difference between the real ones and the counterfeit is its weight.

I give you a balance scale (two sides, you put a weight on each side. Whichever side drops down is heavier; if the two sides weigh the same the two sides will stay in the middle). Using the scale only THREE times, can you figure out which coin is the counterfeit? KEEP IN MIND --> you do NOT know if the coin weighs more or less than the others.


the coins :
ABCDEFGHIJK

weigh:
ABC & DEF

-if they are the same
-weigh ABC and GHI
-if they are the same K is counterfiet
--if they are different weigh G & H if this pair is the same I is counterfiet
--if G & H are different the counterfiet one is the same as how GHI compared to ABC (ex. if GHI was heavier then ABC and G is heavier then H then G is counterfiet)

if ABC & DEF were different
-weigh ABC and GHI
-if they are the same weigh D & E
-if they are the same F is counterfiet
--if D & E are different then the counterfiet one matches DEF compared to ABC (see comparing G & H above)

if ABC & GHI are different:
-weigh G & H (same as above)
-if they are different weigh G & H if this pair is the same I is counterfiet
-if G & H are different the counterfiet one is the same as how GHI compared to ABC (ex. if GHI was heavier then ABC and G is heavier then H then G is counterfiet)

I think i covered all posibilities.

[LuTze]

Originally posted by Streetwolf

Riddle #2: I put a blindfold on you and sit you down in front of a table. I have a piggy bank full of pennies, which I dump onto the table. There are a very large number of pennies. I tell you that 128 of the pennies are heads up and the rest are tails up. How can you create two subgroups of pennies, each with the same number of heads facing up?



I think you can actually feel the difference between the head and tail side can't you?
Edit* yeah i just grabbed some pennies and the tail side of a penny has a very distinct texture.
-------------------------
But other then that since you just dumped them on the table they should have landed equally heads and tails (going by ideal probability here). So there are 256 pennies on the table, just split them into piles and with some luck (and more idealistic probability) they should be evenly split.
-------------------------------------------
Make two piles with all the pennies on their sides so you there are 0 heads in each pile?

[LuTze]

Originally posted by t00t
Mass is measured in kilograms, weight is measured in newtons. Unless americans measure it in pounds?!

and yes the pound is the english unit of force common example would be PSI on a tire.
However in everyday life the pound is used like a gram or kilo would be. Many things are labled in pounds over ounces (our unit of mass). and just to confuse matters more our basic unit of volume is also called an ounce.

Fuck you England.

[Streetwolf]

Log Y is base 10. That's always the assumption. The base has to be written or it is ALWAYS base 10.

I said which weighs more, a pound of feathers or a pound of gold? When one measures feathers they use avoirdupois pounds. When one measures gold they use troy pounds. I never said anything contrary to that. They are both pounds, as stated in the problem.

Lutze, the heads/tails problem isn't correct. Do it without feeling which coins are which. No putting them on the sides :). Remember only TWO subgroups - that means all the quarters are used.

For the 12 coin problem - you never mentioned coin J.

[LuTze]

bah yeah i completly ignored J :(
could you just change the riddle to 10 coins instead of 11?

and i'm saying in the other one you do make two piles. They should fall equally into heads and tails. If there are 128 heads then 256 coins total. and you do just make two piles. doing it randomply should give you two even piles.

[LuTze]

Originally posted by LuTze
the coins :
ABCDEFGHIJK

weigh:
ABC & DEF

-if they are the same
-weigh ABC and GHI
-if they are the same K is counterfiet
--if they are different weigh G & H if this pair is the same I is counterfiet
--if G & H are different the counterfiet one is the same as how GHI compared to ABC (ex. if GHI was heavier then ABC and G is heavier then H then G is counterfiet)

if ABC & DEF were different
-weigh ABC and GHI
-if they are the same weigh D & E
-if they are the same F is counterfiet
--if D & E are different then the counterfiet one matches DEF compared to ABC (see comparing G & H above)

if ABC & GHI are different:
-weigh G & H (same as above)
-if they are different weigh G & H if this pair is the same I is counterfiet
-if G & H are different the counterfiet one is the same as how GHI compared to ABC (ex. if GHI was heavier then ABC and G is heavier then H then G is counterfiet)

I think i covered all posibilities.

Ok after the 2nd step, (ABCDEFGHI are all the same) weigh J & A if they are the same K is counterfeit if they are different J is counterfeit.

The rest of solution puts the counterfeit coin in A-I so i think its good now.

I still dont' know about those pennies though.

[Streetwolf]

Nope still wrong.

Everything is correct until the last part.

Okay so you weighed ABC to DEF and they were different. So it's either in the ABC pile or the DEF pile.

Now you weigh ABC to GHI. If they are the same, you know it's DEF. If they are different, you just jump to weighing GHI.

But at this point, it could be either in the ABC pile or the GHI pile. You just assume it's in the GHI pile. There's still the possibility it's either A, B, or C.

[LuTze]

oops in that last step the counterfeit coin is in ABC cause ABC was different from DEF and GHI

the coins :
ABCDEFGHIJK

weigh:
ABC & DEF

-if ABC & DEF are the same
-weigh ABC and GHI
-if ABC & GHI are the same weigh J & A
-if J & A are the same K is counterfeit
-if J & A are different J is counterfeit.
--if ABC & DEF are different weigh G & H if this pair is the same I is counterfiet
--if G & H are different the counterfiet one is the same as how GHI compared to ABC (ex. if GHI was heavier then ABC and G is heavier then H then G is counterfiet)

if ABC & DEF were different
-weigh ABC and GHI
-if they are the same weigh D & E
-if they are the same F is counterfiet
--if D & E are different then the counterfiet one matches DEF compared to ABC (see comparing G & H above)

if ABC & GHI are different: (counterfeit coin is in ABC)
-weigh A & B
-if they are different weigh G & H if this pair is the same C is counterfiet
-if A & B are different the counterfiet one is the same as how ABC compared to GHI (See comparing G & H above)

correct now?

[Streetwolf]

Wait a minute... I knew something was wrong here... there are 12 coins!! A through K is only 11!!

LOL sorry for not noticing sooner... I solved it a completely different way and was about to kick myself when I saw your way was easier...

Keep trying!

[LuTze]

I failed comprehensive reading as a child.

[LuTze]

Originally posted by Streetwolf

Riddle #2: I put a blindfold on you and sit you down in front of a table. I have a piggy bank full of pennies, which I dump onto the table. There are a very large number of pennies. I tell you that 128 of the pennies are heads up and the rest are tails up. How can you create two subgroups of pennies, each with the same number of heads facing up?



Ok given 12 coins where R = real and U = unknown

make 3 groups of 4 (assume unknown until proven otherwise)

UUUU UUUU UUUU

1) compare two of the groups
case 1 where the two groups are the same you know have:
RRRRRRRR UUUU

2) compare two unknows to two real ones
wether they are different or the same you now only have two unkowns

3) compare one of the unknows to a real ones.
If it is different it is fake, otherwise the unmeasured one is fake

case two where after the original measurement they were different
you now have UUUU UUUU RRRR

but we need to discriminate between the unknowns in the heavier group and the unknowns from the lighter group (L & H).
So we have:
LLLL HHHH RRRR

2) compare LLHHH & HRRRR with left over coins LL

case 1: they are the same
you now have 10 real couns and LL
3) compare L & L
the lighter one is the fake

case 2: the left side (one with all unknow coins was lighter)
the coins now become ( with the coins in the same order as step 2)
LLRRR HRRRR RR
3) weigh L & L
if they are different the lighter one is fake
if they are the same the H is fake


case 3: the side with the real coins was lighter
you now have again in the same order as from step 2
RRHHH RRRRR RR

3) weigh H & H
if they are the same then the third H is the faKe
otherwise the heavier one is the fake





i think this is right

[Streetwolf]

Looks about right.

Here's my solution:

ABCDEFGHIJKL are the coins.

Step 1: Measure abcd-efgh.

If they balance:
Step 2: Measure ab-ij (a and b are normal weights)

If they balance:
Step 3: Measure a-k
If it balances, l is the culprit. If it tips, k is.

If they do not balance:
Step 3: Measure i-j. Whichever coin remains in the SAME position
(top/bottom) as it did in step 2 is the culprit)

**************************************

If they do not balance in step 1 (here's the tricky part):
Step 2: Measure abef-ijcg (i and j are normal. e,f,c have swapped
spots [top/bottom]. a,b,g have not been touched. d and h have been removed. Three swapped, three same, two removed, two normal coins added).

If they balance:
Step 3: Measure a-d.
If it balances, h is the culprit. If it tips, d is.

If they do not balance:

If the scale remains tipped in the same direction:
Step 3: Measure ag-ij. Obviously switching/removing coins had
no effect, therefore the culprit is one of the three coins that stayed put. If it balances, b is the culprit. If it does not balance, whichever coin (a,g) remained in the same position (top/bottom) as in step 2 is the culprit.

If the scale tips in the oppositite direction as in step 2:
Step 3: Measure ec-ij. Obviously switching the coins DID have an effect, which means that it is either e, f, or c. If it balances, f is the culprit. If it does not balance, whichever coin (e,c) remained in the same position (top/bottom) as in step 2 is the culprit.

[Moniker]

I never said anything contrary to that. Yes, but you see, that's your responsibility to state it. The burden lies on the asker of the question to state the information they need to know.

Hence, the answer "they are both the same" is correct, just like "one is heavier" is also correct. I mean, what would be the possibilities of I said "What weighs more, 2 of a type of weight unit, or 2 of a type of another weight unit?"

If you leave loose ends, then the number of possible answers increases.

SO THERE, I AM RIGHT NO MATTER WHAT, MWAAHAHAHAHAHAHAH!!!

[Streetwolf]

http://www.ripleysf.com/ripley/kids/gold.html

The first site I got when I did a search :).

Gold is ALWAYS measured in troy pounds. No exceptions. Your problem for not knowing it ;).

[CountBubba]

lol i kept reading the first riddle wrong...i thought i had to find both the counterfeit coin and whether it was heavier or lighter in each situation...and i kept kicking myself because i could only narrow it down to two coins, while also figuring out the weight.

[LuTze]

Originally posted by Streetwolf
http://www.ripleysf.com/ripley/kids/gold.html

The first site I got when I did a search :).

Gold is ALWAYS measured in troy pounds. No exceptions. Your problem for not knowing it ;).

gold CAN be measured in any unit. Its not gonna self destruct or give improper physical characteristics if you mass it in some other unit. We arn't at a jewler's convention or anything.

Also i've heard the riddle before years ago and the answer then was that they were the same :(

What about those damn pennies ?
Do you rely on probabilities being ideal?

[Moniker]

gold CAN be measured in any unit. Its not gonna self destruct or give improper physical characteristics if you mass it in some other unit. We arn't at a jewler's convention or anything. ^^^^

You can't win this argument. Ambiguity is the path to destruction.

[Streetwolf]

Forget that freakin gold / feather riddle. It's over. It's obvious we aren't going to agree.

The penny riddle - for argument's sake, let's say there are NOT 256 pennies on the table. There might be more, or there might be fewer. But it is not a 1:1 ratio heads:tails.

[LuTze]

I have no clue on the pennies, you can't tell anything about the set other then you can flip everything and get 128 tails instead. I'm thinking you could stack them ontop of eachother but then you still only have a 50/50 short at being right.

hint, answer, anything?

[Streetwolf]

Hint!!!!!



























You do flip coins over in the process.

[k9black`]

Len always has it before. Paul takes it behind. Bryan has never had it at all. Girls can only have it once. Boys don't need it. Mrs. Mulligan, the widow, has it twice in a row. Dr. Lowell of Harvard has it twice as bad at the end as at the beginning. What is it?

[Streetwolf]

L.

[dr_tofu]

lol Street. After I read it a couple of times I understood why you said "l".
Good one k9black... next riddle?

[Streetwolf]

You still didn't answer my 2nd one.

[SithDrummer]

Question: Will the other computer tell me that this door (point to a door) leads to freedom?

If it says no, go through the door you pointed to.
If it says yes, go through the opposite door.

[ElevatioN]

dude that was totally on yugioh

[Countess_Liz]

easy one

when is a door not a door?

[Moniker]

I've got a riddle: how many people does it take to resurrect a completely dead, buried-in-the ground thread?

Just one.

[[RiCE]cancer]

when is a door not a door?

When it's ajar.

[Marneus]

Originally posted by ZfactoR-CaiM-
wtf is yugioh?

i was told that riddle by my father when i was like 8 or 9...

(unless you were not talking to me)


I first heard that riddle when I watched Labrynth. it was set up a little differently, but was basically the same thing...


***Riddle***

how many people can read hex if only you and dead people can read it?

[Marneus]

wrong...

[Forgotten]

This isn't quite classified as a riddle, more of a brain teaser, but I always found it interesting. As a disclaimer, I do not know the answer, nor do I know if there's really an "answer," it's more of something to think about and try to explain.

Three guys go to a motel. The rooms cost $30 for the night, so they rent a room. Each guy pays $10 to even the costs. After they go to the room, the clerk realizes that the room is actually $25 for the night. He gives the bell boy $5 to return to the men. Since the $5 cannot be evenly distributed amongst the three men, he decides to give each man back $1 and keep $2 for himself.

If each man receives $1 back, that would mean they each paid $9. That means alltogether, the men paid $27. The bell boy kept $2, which, added to the $27 the men paid, equals $29. Where's the other dollar?

[Marneus]

there is no extra dollar.

if they pay $30,
and are each returned $1
and the bellboy keeps $2,

then


$25 + 3($1) + 2 = $30

[Marneus]

Why does my post not explain anything...


look at the numbers....


the wording is decieving in the riddle....


the bell hops 2 dollars is figured into the 27 paid......

so, to figure it out propperly.. don't ask why the bell hops 2 dollars only equals 29... becuase his 2 dollars are all ready accounted for... you need to see that the 27 was paid, and 3 were returned... 27 and 3 is clearly 30


******************

how many people can read hex if only you and dead people can read it?

[BluRRPy]

You don't add the $2, you subtract it. That is what is misleading about the question.

When they got the $5 back, they didn't pay $30, they paid $25.

He gives them each a dollar back, so they each paid $9, amounting to $27.

Then the bellhop keeps the $2, which had he givin back to them, would be another ~$0.67 cents back. Which would be subtracing another $2 from 27, giving you 25.

The question tricks you into thinking they paid $30 still.

[Penguin]

Originally posted by Marneus
how many people can read hex if only you and dead people can read it?

No one...because you can't 'read' hex, only computers can.

Or just 1 person, since you can miraculously "read" hex.

[Penguin]

Or is the answer 57006?

[Marneus]

ding ding ding...


57006 is correct...

[BluRRPy]

You should put it in caps or something. That was just stupid.